3a^2+10-72=0

Solution for 3a^2+10-72=0 equation:

3a^2+10-72=0

We add all the numbers together, and all the variables

3a^2-62=0

a = 3; b = 0; c = -62;
Δ = b2-4ac
Δ = 02-4·3·(-62)
Δ = 744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{744}=\sqrt{4*186}=\sqrt{4}*\sqrt{186}=2\sqrt{186}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{186}}{2*3}=\frac{0-2\sqrt{186}}{6}
=-\frac{2\sqrt{186}}{6}
=-\frac{\sqrt{186}}{3}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{186}}{2*3}=\frac{0+2\sqrt{186}}{6}
=\frac{2\sqrt{186}}{6}
=\frac{\sqrt{186}}{3}
$